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In how many ways can we arrange $5$ blue, $3$ yellow and $3$ orange balls in a circle such...

Discussion in 'Mathematics' started by Kedolind, Oct 8, 2018.

  1. Kedolind

    Kedolind Guest

    I read multiple approaches on how to solve this problem. However, I'm still not sure on how to do it as I am only acquainted with basic combinatorics. (clockwise and counterclockwise are considered the same)

    My first approach was to calculate the total number of calculations and then get rid of the permutations that include two of equal color next to each other.

    There are 11 Balls; Therefore the number of permutations should be: 11! = 39916800

    Getting rid of the perms where two adjacent balls are equal in color is the part i can't figure out. (If this is even the right approach to this)

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